What is taylor cos(2x),0 ?

The answer to taylor cos(2x),0 is 1-2x^2+2/3 x^4-4/45 x^6+2/315 x^8+\ldots

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taylor cos(2x),0

taylor

cos (2 x), 0

1 - 2 x^{2} + \frac{2}{3} x^{4} - \frac{4}{45} x^{6} + \frac{2}{315} x^{8} + \dots

Solution steps

Apply the Taylor Formula

= 1 + \frac{\frac{d}{d x} ( cos ( 2 x ) ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( cos ( 2 x ) ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( cos ( 2 x ) ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 1 + \frac{0}{1 !} x + \frac{- 4}{2 !} x^{2} + \frac{0}{3 !} x^{3} + \frac{16}{4 !} x^{4} + \frac{0}{5 !} x^{5} + \frac{- 64}{6 !} x^{6} + \frac{0}{7 !} x^{7} + \frac{256}{8 !} x^{8} + \dots

Refine

= 1 - 2 x^{2} + \frac{2}{3} x^{4} - \frac{4}{45} x^{6} + \frac{2}{315} x^{8} + \dots

\frac{\partial}{\partial t} (r cos (t) sin (s))

\frac{d}{d x} (x (x - 4)^{3})

(\frac{x}{x ^{3} - 1})^{^{'}}

\frac{d}{d x} (\frac{4 - 4 x}{3 x ^{\frac{2}{3}}})

e^{2 x} + 1

What is taylor cos(2x),0 ?
The answer to taylor cos(2x),0 is 1-2x^2+2/3 x^4-4/45 x^6+2/315 x^8+\ldots