What is the integral from 0 to infinity of (e^x)/(1+e^x) ?

The integral from 0 to infinity of (e^x)/(1+e^x) is diverges

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integral from 0 to infinity of (e^x)/(1+e^x)

\int_{0}^{\infty} \frac{e ^{x}}{1 + e ^{x}} d x

diverges

Solution steps

\int_{0}^{\infty} \frac{e ^{x}}{1 + e ^{x}} d x

Compute the indefinite integral:

\int \frac{e ^{x}}{1 + e ^{x}} d x = ln ∣ 1 + e^{x} ∣ + C

Compute the boundaries:

\int_{0}^{\infty} \frac{e ^{x}}{1 + e ^{x}} d x =

diverges

= diverges

f (x) = 4 x^{2} + 3 x + 6, (- 4, 58)

\frac{d}{d x} (cos (a x) a)

f (x) = I n (2 x + 1)

\int sec^{4} (x) tan^{2} (x) d x

\frac{d}{d x} ((x + 2 x) e^{x})

What is the integral from 0 to infinity of (e^x)/(1+e^x) ?
The integral from 0 to infinity of (e^x)/(1+e^x) is diverges