What is the tangent of f(x)=x^2+15x+56,\at x=2 ?

The tangent of f(x)=x^2+15x+56,\at x=2 is y=19x+52

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tangent of f(x)=x^2+15x+56,\at x=2

tangent of

f (x) = x^{2} + 15 x + 56, at x = 2

y = 19 x + 52

Solution steps

Find the tangent point:

(2, 90)

Find the slope of

f (x) = x^{2} + 15 x + 56 : \frac{df ( x )}{d x} = 2 x + 15

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 19

Find the line with slope m=

19

and passing through

(2, 90) : y = 19 x + 52

y = 19 x + 52

6 x, x ((2 1^{2} - x^{2}))

y = e^{x} sin (x), (0, 0)

\int x^{- 1} + x^{\frac{1}{3}} + \frac{5}{3} d x

x \to - 1 lim (x^{2} + 4 x + 3)

\frac{d}{d x} (\frac{1}{2} x^{- \frac{1}{2}})

What is the tangent of f(x)=x^2+15x+56,\at x=2 ?
The tangent of f(x)=x^2+15x+56,\at x=2 is y=19x+52