What is the integral of 50-6.3e^{0.9x} ?

The integral of 50-6.3e^{0.9x} is 50x-6.99999…e^{0.9x}+C

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integral of 50-6.3e^{0.9x}

\int 50 - 6.3 e^{0.9 x} d x

50 x - 6.99999 \dots e^{0.9 x} + C

Solution steps

\int 50 - 6.3 e^{0.9 x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 50 d x - \int 6.3 e^{0.9 x} d x

\int 50 d x = 50 x

\int 6.3 e^{0.9 x} d x = 6.99999 \dots e^{0.9 x}

= 50 x - 6.99999 \dots e^{0.9 x}

Add a constant to the solution

= 50 x - 6.99999 \dots e^{0.9 x} + C

\int (3 x + 2)^{5} d x

\frac{d}{d x} (e^{2 x^{4}})

f (x) = \frac{x}{x ^{2} + 1}

\frac{\partial}{\partial x} (8 x (x^{2} + y^{2})^{- \frac{1}{2}})

f (x) = x^{2} + 13, at x = 6

What is the integral of 50-6.3e^{0.9x} ?
The integral of 50-6.3e^{0.9x} is 50x-6.99999…e^{0.9x}+C