What is the tangent of y=3x^4,(-2,48) ?

The tangent of y=3x^4,(-2,48) is y=-96x-144

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=3x^4,(-2,48)

tangent of

y = 3 x^{4}, (- 2, 48)

y = - 96 x - 144

Solution steps

Find the slope of

y = 3 x^{4} : \frac{d y}{d x} = 12 x^{3}

Compute the slope of

y = 3 x^{4}

(- 2, 48) : m = - 96

Find the line with slope m=

- 96

and passing through

(- 2, 48) : y = - 96 x - 144

y = - 96 x - 144

\frac{d}{d x} (t^{x})

\frac{d}{d x} (sec (\frac{π}{3}))

(x + 2)^{2} y^{^{'}} + 5 (x + 2) y = 16, y (0) = 4

\int 5 x^{- 7} d x

x^{3} y^{2} = x y^{3} + 6, (2, 1)

What is the tangent of y=3x^4,(-2,48) ?
The tangent of y=3x^4,(-2,48) is y=-96x-144