What is the derivative of f(x)=3x^2-4x+1 ?

The derivative of f(x)=3x^2-4x+1 is 6x-4

What is the first derivative of f(x)=3x^2-4x+1 ?

The first derivative of f(x)=3x^2-4x+1 is 6x-4

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derivative of

f (x) = 3 x^{2} - 4 x + 1

6 x - 4

Solution steps

\frac{d}{d x} (3 x^{2} - 4 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (1)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (1) = 0

= 6 x - 4 + 0

Simplify

= 6 x - 4

\frac{d}{d x} (sin (x) sec (x))

\int_{- 2}^{2} 2 d x

y = 3 x^{2} sin (x)

2 y^{^{''}} + 3 y^{^{'}} - 2 y = 25 e^{- 2 t}

\int \frac{5}{9 + 4 r ^{2}} d r

What is the derivative of f(x)=3x^2-4x+1 ?
The derivative of f(x)=3x^2-4x+1 is 6x-4
What is the first derivative of f(x)=3x^2-4x+1 ?
The first derivative of f(x)=3x^2-4x+1 is 6x-4