What is the integral from 0 to 1 of x^{-1/3} ?

The integral from 0 to 1 of x^{-1/3} is 3/2

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integral from 0 to 1 of x^{-1/3}

\int_{0}^{1} x^{- \frac{1}{3}} d x

\frac{3}{2}

Decimal Notation

1.5

Solution steps

\int_{0}^{1} x^{- \frac{1}{3}} d x

Apply the Power Rule

: [\frac{3}{2} x^{\frac{2}{3}}]_{0}^{1}

= [\frac{3}{2} x^{\frac{2}{3}}]_{0}^{1}

Compute the boundaries:

\frac{3}{2}

= \frac{3}{2}

\int 4 x^{3} e^{2 x} d x

\int \frac{17.6 \cdot 15.24}{17.6 \cdot 0 ^{2} + 1}

x \to 0 lim (4 x^{2} + 3)

9 y^{^{''}} - 9 y^{^{'}} - 4 y = 0

\frac{d}{d x} (2 x^{4} - 6 x^{3} - 7 x^{2} + 9)

What is the integral from 0 to 1 of x^{-1/3} ?
The integral from 0 to 1 of x^{-1/3} is 3/2