What is the integral of 4/((1-x^2)^{3/2)} ?

The integral of 4/((1-x^2)^{3/2)} is (4x)/((1-x^2)^{1/2)}+C

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integral of 4/((1-x^2)^{3/2)}

\int \frac{4}{( 1 - x ^{2} ) ^{\frac{3}{2}}} d x

\frac{4 x}{( 1 - x ^{2} ) ^{\frac{1}{2}}} + C

Solution steps

\int \frac{4}{( 1 - x ^{2} ) ^{\frac{3}{2}}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int \frac{1}{( 1 - x ^{2} ) ^{\frac{3}{2}}} d x

Apply Trigonometric Substitution

: \int sec^{2} (u) d u

= 4 \cdot \int sec^{2} (u) d u

Use the common integral:

\int sec^{2} (u) d u = tan (u)

= 4 tan (u)

Substitute back

u = arcsin (x)

= 4 tan (arcsin (x))

Simplify

4 tan (arcsin (x)) : \frac{4 x}{( 1 - x ^{2} ) ^{\frac{1}{2}}}

= \frac{4 x}{( 1 - x ^{2} ) ^{\frac{1}{2}}}

Add a constant to the solution

= \frac{4 x}{( 1 - x ^{2} ) ^{\frac{1}{2}}} + C

x \to + 3 lim (4 - x)

x \to 0 lim (x + x)

\frac{d}{d x} (c x^{2})

\int \frac{y ^{2} + 34 y + 289}{( y ^{2} + 289 ) ^{2}} d y

(csc (x) + cot (x))^{- 1}

What is the integral of 4/((1-x^2)^{3/2)} ?
The integral of 4/((1-x^2)^{3/2)} is (4x)/((1-x^2)^{1/2)}+C