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Popular >

y^'=y+x^2

Solution

y^{^{'}} = y + x^{2}

Solution

y = - x^{2} - 2 (x + 1) + c_{1} e^{x}

Solution steps

y^{'} (x) = y + x^{2}

Solve linear ODE:

y = - x^{2} - 2 (x + 1) + c_{1} e^{x}

y = - x^{2} - 2 (x + 1) + c_{1} e^{x}

Popular Examples

(dy)/(dx)=(x(e^{x^2}+2))/(6y^2)

\frac{d y}{d x} = \frac{x ( e ^{x^{2}} + 2 )}{6 y ^{2}}

derivative of y=(6sqrt(x)-2)(5sqrt(x)+7)derivative of

y = (6 x - 2) (5 x + 7)

integral from 0 to 4pi of t^2sin(2t)

\int_{0}^{4 π} t^{2} sin (2 t) d t

integral of 2^{4x}

\int 2^{4 x} d x

derivative of x(x-4)

\frac{d}{d x} (x (x - 4))

Frequently Asked Questions (FAQ)

What is the solution for y^'=y+x^2 ?
The solution for y^'=y+x^2 is y=-x^2-2(x+1)+c_{1}e^x