What is the sum from n=0 to infinity of n/(n+1) ?

The sum from n=0 to infinity of n/(n+1) is diverges

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sum from n=0 to infinity of n/(n+1)

n = 0 \sum \infty \frac{n}{n + 1}

diverges

Solution steps

n = 0 \sum \infty \frac{n}{n + 1}

Apply Series Divergence Test:

diverges

= diverges

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n = 1 \sum \infty \frac{1}{( 4 n ^{2} - 1 )}

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What is the sum from n=0 to infinity of n/(n+1) ?
The sum from n=0 to infinity of n/(n+1) is diverges