What is the integral of \sqrt[7]{x^3} ?

The integral of \sqrt[7]{x^3} is 7/10 x^{10/7}+C

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integral of \sqrt[7]{x^3}

\frac{7}{10} x^{\frac{10}{7}} + C

Solution steps

assuming

x \geq 0

= \int x^{\frac{3}{7}} d x

Apply the Power Rule

: \frac{7}{10} x^{\frac{10}{7}}

= \frac{7}{10} x^{\frac{10}{7}}

Add a constant to the solution

= \frac{7}{10} x^{\frac{10}{7}} + C

\frac{d}{d x} (\frac{x ^{2} + 3}{( x - 1 ) ^{3} + ( x + 1 ) ^{3}})

(6, - 5), (2, 3)

f (x) = (\frac{x - 3}{x + 3})^{2}, at x = - 2

y^{^{''}} + 7 y^{^{'}} + 10 y = - 18 t e^{3 t}

\int 4 e^{6 x} d x

What is the integral of \sqrt[7]{x^3} ?
The integral of \sqrt[7]{x^3} is 7/10 x^{10/7}+C