What is the limit as x approaches 0+of x^{9/x} ?

The limit as x approaches 0+of x^{9/x} is 0

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limit as x approaches 0+of x^{9/x}

x \to 0 + lim (x^{\frac{9}{x}})

0

Solution steps

x \to 0 + lim (x^{\frac{9}{x}})

Apply exponent rules

= x \to 0 + lim (e^{\frac{9}{x} l n (x)})

Apply the Limit Chain Rule:

0

= 0

f (x) = x^{2} + 9

\int csc^{2} (2 t) d t

\int_{(- 1)}^{3} - ∣ x - 4 ∣ + 2 d x

x^{2} sin (\frac{1}{x})

\frac{x}{x ^{2} + 81}

What is the limit as x approaches 0+of x^{9/x} ?
The limit as x approaches 0+of x^{9/x} is 0