What is the solution for x(dy)/(dx)+y=x^4y^3 ?

The solution for x(dy)/(dx)+y=x^4y^3 is y= 1/(xsqrt(-x^2+c_{1))},y=-1/(xsqrt(-x^2+c_{1))}

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x(dy)/(dx)+y=x^4y^3

x \frac{d y}{d x} + y = x^{4} y^{3}

y = \frac{1}{x - x ^{2} + c _{1}}, y = - \frac{1}{x - x ^{2} + c _{1}}

Solution steps

x \frac{d y}{d x} + y = x^{4} y^{3}

Solve Bernoulli ODE:

y = \frac{1}{x - x ^{2} + c _{1}}, y = - \frac{1}{x - x ^{2} + c _{1}}

y = \frac{1}{x - x ^{2} + c _{1}}, y = - \frac{1}{x - x ^{2} + c _{1}}

y^{^{'}} + 2 x^{2} = 0

\int \frac{3 + x + x ^{2}}{x} d x

\frac{d}{d x} (\frac{150000}{( 4 x + 75 ) ^{2}})

\frac{d}{d x} (arctan (\frac{2}{x}))

\frac{d}{d x} (cos (5 x^{2}))

What is the solution for x(dy)/(dx)+y=x^4y^3 ?
The solution for x(dy)/(dx)+y=x^4y^3 is y= 1/(xsqrt(-x^2+c_{1))},y=-1/(xsqrt(-x^2+c_{1))}