What is the tangent of f(x)=3sqrt(x),\at x=4 ?

The tangent of f(x)=3sqrt(x),\at x=4 is y= 3/4 x+3

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tangent of f(x)=3sqrt(x),\at x=4

tangent of

f (x) = 3 x, at x = 4

y = \frac{3}{4} x + 3

Solution steps

Find the tangent point:

(4, 6)

Find the slope of

f (x) = 3 x : \frac{df ( x )}{d x} = \frac{3}{2 x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{3}{4}

Find the line with slope m=

\frac{3}{4}

and passing through

(4, 6) : y = \frac{3}{4} x + 3

y = \frac{3}{4} x + 3

\int \frac{4 x ^{2} - 49}{x ^{3}} d x

\frac{x}{5 x + 2}

\int \frac{6 e ^{6 t}}{3 + e ^{6 t}} d t

x \to \infty lim (e^{x} + x)

y = a^{3} + cos^{3} (x)

What is the tangent of f(x)=3sqrt(x),\at x=4 ?
The tangent of f(x)=3sqrt(x),\at x=4 is y= 3/4 x+3