What is the solution for y^{''}=-9sin(5x) ?

The solution for y^{''}=-9sin(5x) is y= 9/25 sin(5x)+c_{1}x+c_{2}

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y^{''}=-9sin(5x)

y^{^{''}} = - 9 sin (5 x)

y = \frac{9}{25} sin (5 x) + c_{1} x + c_{2}

Solution steps

y^{''} (x) = - 9 sin (5 x)

Solve

y^{''} (x) = - 9 sin (5 x) : y^{'} (x) = \frac{9}{5} cos (5 x) + c_{1}

Solve

y^{'} (x) = \frac{9}{5} cos (5 x) + c_{1} : y = \frac{9}{25} sin (5 x) + c_{1} x + c_{2}

y = \frac{9}{25} sin (5 x) + c_{1} x + c_{2}

\frac{\partial}{\partial x} (\frac{2}{x} - n)

\int (8 t^{3} - 6 t^{- 2}) d t

x \to - 1^{- 1} lim (\frac{x}{x + 1})

\int \frac{9}{x + 9 + x} d x

f (x) = x^{2} (1 - 8 x)

What is the solution for y^{''}=-9sin(5x) ?
The solution for y^{''}=-9sin(5x) is y= 9/25 sin(5x)+c_{1}x+c_{2}