What is (\partial)/(\partial y)(2y+z) ?

The answer to (\partial)/(\partial y)(2y+z) is 2

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(\partial)/(\partial y)(2y+z)

\frac{\partial}{\partial y} (2 y + z)

2

Solution steps

\frac{\partial}{\partial y} (2 y + z)

Treat

z

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 y) + \frac{\partial}{\partial y} (z)

\frac{\partial}{\partial y} (2 y) = 2

\frac{\partial}{\partial y} (z) = 0

= 2 + 0

Simplify

= 2

x \to 2 lim (\frac{2 x + 3}{x - 2})

\int \frac{1}{y - 3} d y

\int (\frac{2 x ^{4} - 8 x ^{3} - 6 x ^{2} + 4}{x ^{3}}) d x

\int_{1}^{3} \frac{ln ( 2 x )}{x ^{2}} d x

x \to 2 lim (- x^{2} + x - 2)

What is (\partial)/(\partial y)(2y+z) ?
The answer to (\partial)/(\partial y)(2y+z) is 2