What is area y=-x^2-2x+3,y=-x+1 ?

The answer to area y=-x^2-2x+3,y=-x+1 is 9/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=-x^2-2x+3,y=-x+1

area

y = - x^{2} - 2 x + 3, y = - x + 1

\frac{9}{2}

Decimal

4.5

Solution steps

Apply the area formula:

\int_{- 2}^{1} - x^{2} - 2 x + 3 - (- x + 1) d x

Solve

\int_{- 2}^{1} - x^{2} - 2 x + 3 - (- x + 1) d x : \frac{9}{2}

The area is:

= \frac{9}{2}

\int \frac{( x - 1 )}{( x ^{2} - 2 x - 35 ) ^{7}} d x

\frac{9}{t}

y = \frac{e ^{4 x^{2 + 1}}}{8}

\frac{\partial}{\partial y} (x^{2} y^{4} + z^{3})

\int \frac{x ^{2} - 289}{x} d x