What is the derivative of d-b-ax-d/(x^2) ?

The derivative of d-b-ax-d/(x^2) is (2d)/(x^3)-a

What is the first derivative of d-b-ax-d/(x^2) ?

The first derivative of d-b-ax-d/(x^2) is (2d)/(x^3)-a

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\frac{d}{d x} (d - b - a x - \frac{d}{x ^{2}})

\frac{2 d}{x ^{3}} - a

Solution steps

\frac{d}{d x} (d - b - a x - \frac{d}{x ^{2}})

Treat

b, a, d

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{dd}{d x} - \frac{d b}{d x} - \frac{d}{d x} (a x) - \frac{d}{d x} (\frac{d}{x ^{2}})

\frac{dd}{d x} = 0

\frac{d b}{d x} = 0

\frac{d}{d x} (a x) = a

\frac{d}{d x} (\frac{d}{x ^{2}}) = - \frac{2 d}{x ^{3}}

= 0 - 0 - a - (- \frac{2 d}{x ^{3}})

Simplify

= \frac{2 d}{x ^{3}} - a

9 x

f (x) = 4 sin (x) + 7 cos (x)

\frac{\partial}{\partial x} (x^{4} sin (x y^{3}))

\int \frac{( arctan ( 5 x ) )}{1 + 25 x ^{2}} d x

\frac{d}{d x} (- x^{5})

What is the derivative of d-b-ax-d/(x^2) ?
The derivative of d-b-ax-d/(x^2) is (2d)/(x^3)-a
What is the first derivative of d-b-ax-d/(x^2) ?
The first derivative of d-b-ax-d/(x^2) is (2d)/(x^3)-a