What is the integral of cot^2(x) ?

The integral of cot^2(x) is -x-cot(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of cot^2(x)

\int cot^{2} (x) d x

- x - cot (x) + C

Solution steps

\int cot^{2} (x) d x

Rewrite using trig identities

= \int - 1 + csc^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 1 d x + \int csc^{2} (x) d x

\int 1 d x = x

\int csc^{2} (x) d x = - cot (x)

= - x - cot (x)

Add a constant to the solution

= - x - cot (x) + C

\frac{d}{d x} (ln (7 x))

\frac{d}{d x} (2 ∣ x - 3 ∣ - 3 ∣ x - 2 ∣)

\int \frac{( 2 x - 1 )}{( x - 1 ) ( x - 2 )} d x

\frac{e ^{x}}{\frac{d y}{d x}} = (1 + e^{x}) y

y^{^{''}} - 6 y^{^{'}} + 25 y = 50 t^{3} - 36 t^{2} - 63 t + 18