What is the solution for y^'+8x^2y=x^2 ?

The solution for y^'+8x^2y=x^2 is y=(e^{(-8x^3+c_{1})/3})/(8)+1/8

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y^'+8x^2y=x^2

y^{^{'}} + 8 x^{2} y = x^{2}

y = \frac{e ^{\frac{- 8 x ^{3} + c _{1}}{3}}}{8} + \frac{1}{8}

Solution steps

y^{'} (x) + 8 x^{2} y = x^{2}

Solve separable ODE:

y = \frac{e ^{\frac{- 8 x ^{3} + c _{1}}{3}}}{8} + \frac{1}{8}

y = \frac{e ^{\frac{- 8 x ^{3} + c _{1}}{3}}}{8} + \frac{1}{8}

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What is the solution for y^'+8x^2y=x^2 ?
The solution for y^'+8x^2y=x^2 is y=(e^{(-8x^3+c_{1})/3})/(8)+1/8