What is (\partial)/(\partial x)(x+y+z^2) ?

The answer to (\partial)/(\partial x)(x+y+z^2) is 1

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(\partial)/(\partial x)(x+y+z^2)

\frac{\partial}{\partial x} (x + y + z^{2})

1

Solution steps

\frac{\partial}{\partial x} (x + y + z^{2})

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (y) + \frac{\partial}{\partial x} (z^{2})

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (z^{2}) = 0

= 1 + 0 + 0

Simplify

= 1

e^{- 11 x}

\int (4 - x^{2})^{2} d x

\int_{2}^{4} \frac{6 + u ^{2}}{u ^{3}} d u

x \to 4 lim (2 x + 1)

\frac{d}{d y} (e^{y^{2}})

What is (\partial)/(\partial x)(x+y+z^2) ?
The answer to (\partial)/(\partial x)(x+y+z^2) is 1