What is the limit as x approaches pi/2 of sin(2x) ?

The limit as x approaches pi/2 of sin(2x) is 0

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limit as x approaches pi/2 of sin(2x)

x \to \frac{π}{2} lim (sin (2 x))

0

Solution steps

x \to \frac{π}{2} lim (sin (2 x))

Plug in the value

x = \frac{π}{2}

= sin (2 \cdot \frac{π}{2})

Simplify

sin (2 \cdot \frac{π}{2}) : 0

= 0

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t^{3} y^{^{'}} + 4 t^{2} y = e^{- t}, y (1) = 0

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What is the limit as x approaches pi/2 of sin(2x) ?
The limit as x approaches pi/2 of sin(2x) is 0