What is (\partial)/(\partial x)(-9x^2-7y^2) ?

The answer to (\partial)/(\partial x)(-9x^2-7y^2) is -18x

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(\partial)/(\partial x)(-9x^2-7y^2)

\frac{\partial}{\partial x} (- 9 x^{2} - 7 y^{2})

- 18 x

Solution steps

\frac{\partial}{\partial x} (- 9 x^{2} - 7 y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (9 x^{2}) - \frac{\partial}{\partial x} (7 y^{2})

\frac{\partial}{\partial x} (9 x^{2}) = 18 x

\frac{\partial}{\partial x} (7 y^{2}) = 0

= - 18 x - 0

Simplify

= - 18 x

y^{^{''}} + 169 y = sec (13 x)

\int \frac{16 x ^{2}}{( x - 21 ) ( x + 7 ) ^{2}} d x

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\frac{d y}{d x} = b \cdot (1 - y) \cdot y

\int_{0}^{\frac{π}{3}} sin^{2} (x) d x

What is (\partial)/(\partial x)(-9x^2-7y^2) ?
The answer to (\partial)/(\partial x)(-9x^2-7y^2) is -18x