What is the integral from 0 to 1 of 1/(x^0) ?

The integral from 0 to 1 of 1/(x^0) is 1

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integral from 0 to 1 of 1/(x^0)

\int_{0}^{1} \frac{1}{x ^{0}} d x

1

Solution steps

\int_{0}^{1} \frac{1}{x ^{0}} d x

Apply the Power Rule

: [x]_{0}^{1}

= [x]_{0}^{1}

Compute the boundaries:

1

= 1

y^{2} - 5 x = 4, x - y = 2

x^{\frac{1}{2}}

\frac{3 x d x}{x ^{2} + 2} = - \frac{y d y}{y ^{2} + 1}

\frac{d}{d x} (\frac{4 x}{x ^{2} + 3})

\frac{d y}{d x} = \frac{cos ( 7 x )}{e ^{7 y}}

What is the integral from 0 to 1 of 1/(x^0) ?
The integral from 0 to 1 of 1/(x^0) is 1