What is the solution for xy^2dx+(x^2y^2+x^2y)dy=0 ?

The solution for xy^2dx+(x^2y^2+x^2y)dy=0 is y=\W((c_{1})/x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

xy^2dx+(x^2y^2+x^2y)dy=0

x y^{2} d x + (x^{2} y^{2} + x^{2} y) d y = 0

y = W (\frac{c _{1}}{x})

Solution steps

x y^{2} d x + (x^{2} y^{2} + x^{2} y) d y = 0

Solve separable ODE:

y = W (\frac{c _{1}}{x})

y = W (\frac{c _{1}}{x})

\frac{6 x d y}{d x} + y = x^{7}

\int 4 x^{3} e^{3 x^{4}} d x

\frac{d}{d x} (5 arctan (x - 1 + x^{2}))

\frac{d}{d x} (\frac{x}{( x - 6 ) ^{2}})

- \frac{4 x}{y}

What is the solution for xy^2dx+(x^2y^2+x^2y)dy=0 ?
The solution for xy^2dx+(x^2y^2+x^2y)dy=0 is y=\W((c_{1})/x)