What is the d/(dy)(arcsin(x-y)) ?

The d/(dy)(arcsin(x-y)) is -1/(sqrt(1-x^2+2xy-y^2))

What is the first d/(dy)(arcsin(x-y)) ?

The first d/(dy)(arcsin(x-y)) is -1/(sqrt(1-x^2+2xy-y^2))

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\frac{d}{d y} (arcsin (x - y))

- \frac{1}{1 - x ^{2} + 2 x y - y ^{2}}

Solution steps

\frac{d}{d y} (arcsin (x - y))

Treat

x

as a constant

Apply the chain rule:

\frac{1}{1 - ( x - y ) ^{2}} \frac{d}{d y} (x - y)

= \frac{1}{1 - ( x - y ) ^{2}} \frac{d}{d y} (x - y)

\frac{d}{d y} (x - y) = - 1

= \frac{1}{1 - ( x - y ) ^{2}} (- 1)

Simplify

\frac{1}{1 - ( x - y ) ^{2}} (- 1) : - \frac{1}{1 - x ^{2} + 2 x y - y ^{2}}

= - \frac{1}{1 - x ^{2} + 2 x y - y ^{2}}

\frac{\partial}{\partial y} (\frac{1}{x y z ^{2}})

\int \frac{3}{x} - \frac{x x}{4} d x

\frac{d}{d x} (\frac{( x + 1 ) ( 2 x - 5 )}{2 x + 1})

8 x

\int \frac{x}{ln ( x )} d x

What is the d/(dy)(arcsin(x-y)) ?
The d/(dy)(arcsin(x-y)) is -1/(sqrt(1-x^2+2xy-y^2))
What is the first d/(dy)(arcsin(x-y)) ?
The first d/(dy)(arcsin(x-y)) is -1/(sqrt(1-x^2+2xy-y^2))