What is the derivative of ((x^2-8x-17))/((x+2)) ?

The derivative of ((x^2-8x-17))/((x+2)) is (x^2+4x+1)/((x+2)^2)

What is the first derivative of ((x^2-8x-17))/((x+2)) ?

The first derivative of ((x^2-8x-17))/((x+2)) is (x^2+4x+1)/((x+2)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

\frac{( x ^{2} - 8 x - 17 )}{( x + 2 )}

\frac{x ^{2} + 4 x + 1}{( x + 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 8 x - 17}{x + 2})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} - 8 x - 17 ) ( x + 2 ) - \frac{d}{d x} ( x + 2 ) ( x ^{2} - 8 x - 17 )}{( x + 2 ) ^{2}}

\frac{d}{d x} (x^{2} - 8 x - 17) = 2 x - 8

\frac{d}{d x} (x + 2) = 1

= \frac{( 2 x - 8 ) ( x + 2 ) - 1 \cdot ( x ^{2} - 8 x - 17 )}{( x + 2 ) ^{2}}

Simplify

\frac{( 2 x - 8 ) ( x + 2 ) - 1 \cdot ( x ^{2} - 8 x - 17 )}{( x + 2 ) ^{2}} : \frac{x ^{2} + 4 x + 1}{( x + 2 ) ^{2}}

= \frac{x ^{2} + 4 x + 1}{( x + 2 ) ^{2}}

cos (e^{x^{4} c o s (x)})

\int cot^{5} (2 t) d t

y = \frac{1}{2} 3 x

2 y^{^{''}} + y^{^{'}} + y = 0

t^{2} (5 t + 9)^{3}

What is the derivative of ((x^2-8x-17))/((x+2)) ?
The derivative of ((x^2-8x-17))/((x+2)) is (x^2+4x+1)/((x+2)^2)
What is the first derivative of ((x^2-8x-17))/((x+2)) ?
The first derivative of ((x^2-8x-17))/((x+2)) is (x^2+4x+1)/((x+2)^2)