What is taylor 2x^3-3x^2 ?

The answer to taylor 2x^3-3x^2 is -3x^2+2x^3

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taylor 2x^3-3x^2

taylor

2 x^{3} - 3 x^{2}

- 3 x^{2} + 2 x^{3}

Solution steps

Apply the Taylor Formula

= 0 + \frac{\frac{d}{d x} ( 2 x ^{3} - 3 x ^{2} ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( 2 x ^{3} - 3 x ^{2} ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( 2 x ^{3} - 3 x ^{2} ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 0 + \frac{0}{1 !} x + \frac{- 6}{2 !} x^{2} + \frac{12}{3 !} x^{3} + \frac{0}{4 !} x^{4} + \frac{0}{5 !} x^{5} + \frac{0}{6 !} x^{6} + \frac{0}{7 !} x^{7} + \frac{0}{8 !} x^{8} + \frac{0}{9 !} x^{9} + \frac{0}{10 !} x^{10}

Refine

= - 3 x^{2} + 2 x^{3}

\frac{1}{x - 1}, 0

x \to 1 lim (\frac{sin ( x )}{x})

\frac{3}{( 1 - x ^{2} ) ^{4}}

\frac{d}{d x} ((1 - x^{2})^{- 2})

y^{^{''}} + 5 y^{^{'}} + 6 y = 0, y (0) = 1, y^{^{'}} (0) = 0