What is (\partial)/(\partial x)((47x^2)/((x-y)^2)) ?

The answer to (\partial)/(\partial x)((47x^2)/((x-y)^2)) is -(94xy)/((x-y)^3)

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(\partial)/(\partial x)((47x^2)/((x-y)^2))

\frac{\partial}{\partial x} (\frac{47 x ^{2}}{( x - y ) ^{2}})

- \frac{94 x y}{( x - y ) ^{3}}

Solution steps

\frac{\partial}{\partial x} (\frac{47 x ^{2}}{( x - y ) ^{2}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 47 \frac{\partial}{\partial x} (\frac{x ^{2}}{( x - y ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 47 \cdot \frac{\frac{\partial}{\partial x} ( x ^{2} ) ( x - y ) ^{2} - \frac{\partial}{\partial x} ( ( x - y ) ^{2} ) x ^{2}}{( ( x - y ) ^{2} ) ^{2}}

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} ((x - y)^{2}) = 2 (x - y)

= 47 \cdot \frac{2 x ( x - y ) ^{2} - 2 ( x - y ) x ^{2}}{( ( x - y ) ^{2} ) ^{2}}

Simplify

47 \cdot \frac{2 x ( x - y ) ^{2} - 2 ( x - y ) x ^{2}}{( ( x - y ) ^{2} ) ^{2}} : - \frac{94 x y}{( x - y ) ^{3}}

= - \frac{94 x y}{( x - y ) ^{3}}

\int \frac{x}{x ^{2} + y ^{2}} d x

x \to 0 + lim (0^{x})

y^{^{'}} = y (x y^{5} + 5)

\int sec^{4} (x) tan^{6} (x) d x

t^{2} (\frac{d y}{d t}) + y = 0

What is (\partial)/(\partial x)((47x^2)/((x-y)^2)) ?
The answer to (\partial)/(\partial x)((47x^2)/((x-y)^2)) is -(94xy)/((x-y)^3)