What is the integral from 0 to 3 of 1/(sqrt(x)) ?

The integral from 0 to 3 of 1/(sqrt(x)) is 2sqrt(3)

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integral from 0 to 3 of 1/(sqrt(x))

\int_{0}^{3} \frac{1}{x} d x

23

Decimal

3.46410 \dots

Solution steps

\int_{0}^{3} \frac{1}{x} d x

Apply the Power Rule

: [2 x^{\frac{1}{2}}]_{0}^{3}

= [2 x^{\frac{1}{2}}]_{0}^{3}

Apply radical rule:

a^{\frac{1}{n}} = n a

= [2 x]_{0}^{3}

Compute the boundaries:

23

= 23

\int_{0}^{t} x e^{- x} d x

x y^{^{'}} - y = 2 x^{2} - 2 x - 2

x y^{^{'}} - y = x, y (1) = 10

\int_{0}^{2} π (3 x^{2})^{2} d x

\frac{\partial}{\partial x} (4 x^{2} + 3 y^{4})

What is the integral from 0 to 3 of 1/(sqrt(x)) ?
The integral from 0 to 3 of 1/(sqrt(x)) is 2sqrt(3)