What is area y=x+1,y=9-x^2,x=-1,x=2 ?

The answer to area y=x+1,y=9-x^2,x=-1,x=2 is 39/2

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area y=x+1,y=9-x^2,x=-1,x=2

area

y = x + 1, y = 9 - x^{2}, x = - 1, x = 2

\frac{39}{2}

Decimal

19.5

Solution steps

Apply the area formula:

\int_{- 1}^{2} x + 1 - (9 - x^{2}) d x

Solve

\int_{- 1}^{2} x + 1 - (9 - x^{2}) d x : \frac{39}{2}

The area is:

= \frac{39}{2}

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What is area y=x+1,y=9-x^2,x=-1,x=2 ?
The answer to area y=x+1,y=9-x^2,x=-1,x=2 is 39/2