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Popular >

derivative of (x^4)/(16)+1/(2x^2)

Solution

derivative of

\frac{x ^{4}}{16} + \frac{1}{2 x ^{2}}

Solution

\frac{x ^{3}}{4} - \frac{1}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{x ^{4}}{16} + \frac{1}{2 x ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{4}}{16}) + \frac{d}{d x} (\frac{1}{2 x ^{2}})

\frac{d}{d x} (\frac{x ^{4}}{16}) = \frac{x ^{3}}{4}

\frac{d}{d x} (\frac{1}{2 x ^{2}}) = - \frac{1}{x ^{3}}

= \frac{x ^{3}}{4} - \frac{1}{x ^{3}}

Graph

Popular Examples

integral of 1/(sqrt(16-4x^2))

\int \frac{1}{16 - 4 x ^{2}} d x

integral of 1/(2y+1)

\int \frac{1}{2 y + 1} d y

limit as x approaches infinity of (-3)/x

x \to \infty lim (\frac{- 3}{x})

inverse oflaplace 1/(s(s^2+1))inverse laplace

\frac{1}{s ( s ^{2} + 1 )}

limit as x approaches-2 of 4x^2

x \to - 2 lim (4 x^{2})

Frequently Asked Questions (FAQ)

What is the derivative of (x^4)/(16)+1/(2x^2) ?
The derivative of (x^4)/(16)+1/(2x^2) is (x^3)/4-1/(x^3)
What is the first derivative of (x^4)/(16)+1/(2x^2) ?
The first derivative of (x^4)/(16)+1/(2x^2) is (x^3)/4-1/(x^3)