What is the derivative of f(x)=x^2-2x-3 ?

The derivative of f(x)=x^2-2x-3 is 2x-2

What is the first derivative of f(x)=x^2-2x-3 ?

The first derivative of f(x)=x^2-2x-3 is 2x-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = x^{2} - 2 x - 3

2 x - 2

Solution steps

\frac{d}{d x} (x^{2} - 2 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (2 x) - \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (3) = 0

= 2 x - 2 - 0

Simplify

= 2 x - 2

\frac{d}{d x} (sin (cot (x)))

y = e^{x} cos (x)

\frac{7 s + 5}{( s + 2 ) ( s - 1 )}

\int_{0}^{1} (x^{3}) d x

x cos (2 x)

What is the derivative of f(x)=x^2-2x-3 ?
The derivative of f(x)=x^2-2x-3 is 2x-2
What is the first derivative of f(x)=x^2-2x-3 ?
The first derivative of f(x)=x^2-2x-3 is 2x-2