What is the derivative of y=arcsin(8x+1) ?

The derivative of y=arcsin(8x+1) is 2/(sqrt(-x(4x+1)))

What is the first derivative of y=arcsin(8x+1) ?

The first derivative of y=arcsin(8x+1) is 2/(sqrt(-x(4x+1)))

Popular >

derivative of

y = arcsin (8 x + 1)

\frac{2}{- x ( 4 x + 1 )}

Solution steps

\frac{d}{d x} (arcsin (8 x + 1))

Apply the chain rule:

\frac{1}{1 - ( 8 x + 1 ) ^{2}} \frac{d}{d x} (8 x + 1)

= \frac{1}{1 - ( 8 x + 1 ) ^{2}} \frac{d}{d x} (8 x + 1)

\frac{d}{d x} (8 x + 1) = 8

= \frac{1}{1 - ( 8 x + 1 ) ^{2}} \cdot 8

Simplify

\frac{1}{1 - ( 8 x + 1 ) ^{2}} \cdot 8 : \frac{2}{- x ( 4 x + 1 )}

= \frac{2}{- x ( 4 x + 1 )}

n = 1 \sum \infty \frac{- 3 ^{n}}{8 ^{n}}

e^{2 x} - 3 x

3 e^{x} tan (y) d x + (2 - e^{x}) sec^{2} (y) d y = 0

y = 4 x^{3} - 4 x (- 1)

ln (arccsc (x))

What is the derivative of y=arcsin(8x+1) ?
The derivative of y=arcsin(8x+1) is 2/(sqrt(-x(4x+1)))
What is the first derivative of y=arcsin(8x+1) ?
The first derivative of y=arcsin(8x+1) is 2/(sqrt(-x(4x+1)))