What is the sum from n=1 to infinity of (e^n)/n ?

The sum from n=1 to infinity of (e^n)/n is diverges

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sum from n=1 to infinity of (e^n)/n

n = 1 \sum \infty \frac{e ^{n}}{n}

diverges

Solution steps

n = 1 \sum \infty \frac{e ^{n}}{n}

Apply Series Ratio Test:

diverges

= diverges

t y^{^{'}} + 2 y = t^{2} - t + 1, y (1) = 0.5

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What is the sum from n=1 to infinity of (e^n)/n ?
The sum from n=1 to infinity of (e^n)/n is diverges