What is (\partial)/(\partial x)(-9x^2y^2-cos(y)) ?

The answer to (\partial)/(\partial x)(-9x^2y^2-cos(y)) is -18xy^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(-9x^2y^2-cos(y))

\frac{\partial}{\partial x} (- 9 x^{2} y^{2} - cos (y))

- 18 x y^{2}

Solution steps

\frac{\partial}{\partial x} (- 9 x^{2} y^{2} - cos (y))

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (9 x^{2} y^{2}) - \frac{\partial}{\partial x} (cos (y))

\frac{\partial}{\partial x} (9 x^{2} y^{2}) = 18 y^{2} x

\frac{\partial}{\partial x} (cos (y)) = 0

= - 18 y^{2} x - 0

Simplify

= - 18 x y^{2}

x^{3} + 8

\frac{1}{18 x ^{2}}, x, \frac{x}{8}

\frac{d ^{2}}{d x ^{2}} (e^{- 6 x})

f (x) = 3 e^{x} cos (x), at x = 0

\frac{\partial}{\partial x} (x^{2} + \frac{y}{x})

What is (\partial)/(\partial x)(-9x^2y^2-cos(y)) ?
The answer to (\partial)/(\partial x)(-9x^2y^2-cos(y)) is -18xy^2