What is the integral of sin(x)+e^x ?

The integral of sin(x)+e^x is -cos(x)+e^x+C

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integral of sin(x)+e^x

\int sin (x) + e^{x} d x

- cos (x) + e^{x} + C

Solution steps

\int sin (x) + e^{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sin (x) d x + \int e^{x} d x

\int sin (x) d x = - cos (x)

\int e^{x} d x = e^{x}

= - cos (x) + e^{x}

Add a constant to the solution

= - cos (x) + e^{x} + C

\frac{( 3 s + 4 )}{( s + 2 ) ^{2}}

x \to \infty lim (7 x^{2} + 3 x^{3})

16 x, at x = 16

(5, 0), (8, 15)

\frac{\partial}{\partial x} (\frac{y ^{2}}{( x + y ) ^{2}})

What is the integral of sin(x)+e^x ?
The integral of sin(x)+e^x is -cos(x)+e^x+C