What is the derivative of ln(1+7x) ?

The derivative of ln(1+7x) is 7/(1+7x)

What is the first derivative of ln(1+7x) ?

The first derivative of ln(1+7x) is 7/(1+7x)

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\frac{d}{d x} (ln (1 + 7 x))

\frac{7}{1 + 7 x}

Solution steps

\frac{d}{d x} (ln (1 + 7 x))

Apply the chain rule:

\frac{1}{1 + 7 x} \frac{d}{d x} (1 + 7 x)

= \frac{1}{1 + 7 x} \frac{d}{d x} (1 + 7 x)

\frac{d}{d x} (1 + 7 x) = 7

= \frac{1}{1 + 7 x} \cdot 7

Simplify

\frac{1}{1 + 7 x} \cdot 7 : \frac{7}{1 + 7 x}

= \frac{7}{1 + 7 x}

\frac{d}{d x} (x^{2} 4 x - 9)

\int - cos (u) + \frac{1}{3} cos^{3} (u) d u

(3 x^{2} - 10)^{- 13}

\int (- 3 (\frac{9 x ^{2}}{2}) - 4 x^{3}) d x

y^{^{'}} = \frac{e ^{t}}{3 y ^{2}}

What is the derivative of ln(1+7x) ?
The derivative of ln(1+7x) is 7/(1+7x)
What is the first derivative of ln(1+7x) ?
The first derivative of ln(1+7x) is 7/(1+7x)