What is (\partial}{\partial v}(\frac{u+v)/3) ?

The answer to (\partial}{\partial v}(\frac{u+v)/3) is 1/3

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(\partial}{\partial v}(\frac{u+v)/3)

\frac{\partial}{\partial v} (\frac{u + v}{3})

\frac{1}{3}

Solution steps

\frac{\partial}{\partial v} (\frac{u + v}{3})

Treat

u

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{3} \frac{\partial}{\partial v} (u + v)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{3} (\frac{\partial}{\partial v} (u) + \frac{\partial}{\partial v} (v))

\frac{\partial}{\partial v} (u) = 0

\frac{\partial}{\partial v} (v) = 1

= \frac{1}{3} (0 + 1)

Simplify

= \frac{1}{3}

x \cdot \frac{d y}{d x} - (1 + x) y = x y^{2}

x^{2}, 0, 1

n = 0 \sum \infty (- 1)^{n} x (\frac{x}{4})^{2 n}

\frac{d}{d x} (arctan (1 + x^{2}))

y = sin (sin (sin (x)))

What is (\partial}{\partial v}(\frac{u+v)/3) ?
The answer to (\partial}{\partial v}(\frac{u+v)/3) is 1/3