What is (\partial)/(\partial x)(cos(x)sin(y)) ?

The answer to (\partial)/(\partial x)(cos(x)sin(y)) is -sin(x)sin(y)

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(\partial)/(\partial x)(cos(x)sin(y))

\frac{\partial}{\partial x} (cos (x) sin (y))

- sin (x) sin (y)

Solution steps

\frac{\partial}{\partial x} (cos (x) sin (y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sin (y) \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= sin (y) (- sin (x))

Simplify

= - sin (x) sin (y)

y^{^{''}} - 10 y^{^{'}} + 61 y = 0

\frac{56 s}{s ^{2} + 196}

\frac{d y}{d x} = - 2 x tan (y), y (0) = \frac{π}{2}

\frac{d x}{d t} = x (1 - 0.0004 x)

\int_{1}^{2} 9 \frac{ln ( x )}{x ^{2}} d x

What is (\partial)/(\partial x)(cos(x)sin(y)) ?
The answer to (\partial)/(\partial x)(cos(x)sin(y)) is -sin(x)sin(y)