What is area x=-3,x=-1,y=x^3+8,y=0 ?

The answer to area x=-3,x=-1,y=x^3+8,y=0 is 25/2

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area x=-3,x=-1,y=x^3+8,y=0

area

x = - 3, x = - 1, y = x^{3} + 8, y = 0

\frac{25}{2}

Decimal

12.5

Solution steps

Apply the area formula:

\int_{- 3}^{- 1} x^{3} + 8 d x

Solve

\int_{- 3}^{- 1} x^{3} + 8 d x : \frac{25}{2}

The area is:

= \frac{25}{2}

\frac{\partial}{\partial x} (y^{2} e^{- x})

\frac{\partial}{\partial x} ((A x^{c} + B y^{c})^{\frac{1}{c}})

\frac{\partial}{\partial x} (\frac{18}{x y})

\int_{1}^{6} k x d x

x \to - 2 lim (\frac{x ^{2} - 5}{2 - x})

What is area x=-3,x=-1,y=x^3+8,y=0 ?
The answer to area x=-3,x=-1,y=x^3+8,y=0 is 25/2