What is the first derivative of-2x-2 ?

The first derivative of-2x-2 is -2

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derivative of-2x-2

\frac{d}{d x} (- 2 x - 2)

- 2

Solution steps

\frac{d}{d x} (- 2 x - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 x) - \frac{d}{d x} (2)

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (2) = 0

= - 2 - 0

Simplify

= - 2

\int_{0}^{1} 6 x d x

y = e^{x}, y = x^{2} - 1, x = - 1, x = 1

n = 1 \sum \infty n e^{6 n}

\frac{d y}{d t} - (\frac{3}{t}) \cdot y = 2 t^{3} e^{2 t}, y (1) = 0

\frac{7}{x}