What is area x^2+y^2=6,x=y^2,y=0 ?

The answer to area x^2+y^2=6,x=y^2,y=0 is No Solution

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area x^2+y^2=6,x=y^2,y=0

area

x^{2} + y^{2} = 6, x = y^{2}, y = 0

No Solution

Solution steps

Isolate

y

for

x^{2} + y^{2} = 6 : y = 6 - x^{2}, y = - 6 - x^{2}

Isolate

y

for

x = y^{2} : y = x, y = - x

f_{1} (x) = 6 - x^{2}

f_{2} (x) = - 6 - x^{2}

To find the intersection points solve

f_{i} (x) = f_{j} (x)

6 - x^{2} = - 6 - x^{2} : x = 6, x = - 6

6 - x^{2} = x : x = 2

6 - x^{2} = - x :

No Solution for

x \in R

6 - x^{2} = 0 : x = 6, x = - 6

- 6 - x^{2} = x :

No Solution for

x \in R

- 6 - x^{2} = - x : x = 2

- 6 - x^{2} = 0 : x = 6, x = - 6

x = - x : x = 0

x = 0 : x = 0

- x = 0 : x = 0

Curves not bounded

= No Solution

\frac{d y}{d x}, x^{3} - 3 a x y + y^{3} = 0

x \to π lim (sin (7 x))

\int_{- 2}^{2} (3 u + 1)^{2} d u

\frac{d}{d x} (\frac{x ^{2} + 2}{x ^{3} + 1})

\frac{d}{d x} ((3 x + 7) x^{2})

What is area x^2+y^2=6,x=y^2,y=0 ?
The answer to area x^2+y^2=6,x=y^2,y=0 is No Solution