What is the solution for y^{''}-y^'-2y=3e^{2x} ?

The solution for y^{''}-y^'-2y=3e^{2x} is y=c_{1}e^{2x}+c_{2}e^{-x}+e^{2x}x

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y^{''}-y^'-2y=3e^{2x}

y^{^{''}} - y^{^{'}} - 2 y = 3 e^{2 x}

y = c_{1} e^{2 x} + c_{2} e^{- x} + e^{2 x} x

Solution steps

y^{''} (x) - y^{'} (x) - 2 y = 3 e^{2 x}

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} e^{- x} + e^{2 x} x

y = c_{1} e^{2 x} + c_{2} e^{- x} + e^{2 x} x

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What is the solution for y^{''}-y^'-2y=3e^{2x} ?
The solution for y^{''}-y^'-2y=3e^{2x} is y=c_{1}e^{2x}+c_{2}e^{-x}+e^{2x}x