What is (\partial)/(\partial y)(8xe^{x^2+y^2}) ?

The answer to (\partial)/(\partial y)(8xe^{x^2+y^2}) is 16e^{x^2+y^2}xy

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(8xe^{x^2+y^2})

\frac{\partial}{\partial y} (8 x e^{x^{2} + y^{2}})

16 e^{x^{2} + y^{2}} x y

Solution steps

\frac{\partial}{\partial y} (8 x e^{x^{2} + y^{2}})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 x \frac{\partial}{\partial y} (e^{x^{2} + y^{2}})

Apply the chain rule:

e^{x^{2} + y^{2}} \frac{\partial}{\partial y} (x^{2} + y^{2})

= e^{x^{2} + y^{2}} \frac{\partial}{\partial y} (x^{2} + y^{2})

\frac{\partial}{\partial y} (x^{2} + y^{2}) = 2 y

= 8 x e^{x^{2} + y^{2}} \cdot 2 y

Simplify

= 16 e^{x^{2} + y^{2}} x y

f (x) = 4 x

\frac{d}{d x} (3 ln (x))

\int 4 sec^{3} (x) d x

\int \frac{3 t}{1 - 9 t ^{4}} d t

\int 3 cos (3 x) d x

What is (\partial)/(\partial y)(8xe^{x^2+y^2}) ?
The answer to (\partial)/(\partial y)(8xe^{x^2+y^2}) is 16e^{x^2+y^2}xy