What is the derivative of f(x)=x^2+8x-2 ?

The derivative of f(x)=x^2+8x-2 is 2x+8

What is the first derivative of f(x)=x^2+8x-2 ?

The first derivative of f(x)=x^2+8x-2 is 2x+8

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derivative of

f (x) = x^{2} + 8 x - 2

2 x + 8

Solution steps

\frac{d}{d x} (x^{2} + 8 x - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (8 x) - \frac{d}{d x} (2)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (2) = 0

= 2 x + 8 - 0

Simplify

= 2 x + 8

x \to 0.9 lim (x^{2} - 1)

y = 13 x e^{x}

\frac{d y}{d x} - \frac{2 x ^{3} y}{x ^{4} + 3} = x^{3}

\frac{d}{d x} (2 A x + B)

\frac{d}{d x} (x^{6} ln (5 x))

What is the derivative of f(x)=x^2+8x-2 ?
The derivative of f(x)=x^2+8x-2 is 2x+8
What is the first derivative of f(x)=x^2+8x-2 ?
The first derivative of f(x)=x^2+8x-2 is 2x+8