What is the solution for (dy)/(dx)=e^{2x}+4y ?

The solution for (dy)/(dx)=e^{2x}+4y is y=-(e^{2x})/2+c_{1}e^{4x}

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(dy)/(dx)=e^{2x}+4y

\frac{d y}{d x} = e^{2 x} + 4 y

y = - \frac{e ^{2 x}}{2} + c_{1} e^{4 x}

Solution steps

\frac{d y}{d x} = e^{2 x} + 4 y

Solve linear ODE:

y = - \frac{e ^{2 x}}{2} + c_{1} e^{4 x}

y = - \frac{e ^{2 x}}{2} + c_{1} e^{4 x}

\frac{d}{d x} (3 x + 2 x^{2})

\frac{d y}{d t} = (e^{- 2 t + 3 y})

x \to 6 lim (\frac{x ^{2} - 6}{x + 4})

y = 16 - x^{2}, y = x^{2} - 2

\int \frac{19}{x ( x ^{2} + 4 ) ^{2}} d x

What is the solution for (dy)/(dx)=e^{2x}+4y ?
The solution for (dy)/(dx)=e^{2x}+4y is y=-(e^{2x})/2+c_{1}e^{4x}