What is the integral of 4cos((npix)/4) ?

The integral of 4cos((npix)/4) is (16}{pin}sin(\frac{pinx)/4)+C

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integral of 4cos((npix)/4)

\int 4 cos (\frac{nπ x}{4}) d x

\frac{16}{πn} sin (\frac{πn x}{4}) + C

Solution steps

\int 4 cos (\frac{nπ x}{4}) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int cos (\frac{nπ x}{4}) d x

Apply Integration By Parts

: x cos (\frac{πn x}{4}) - \int - \frac{πn}{4} x sin (\frac{πn x}{4}) d x

= 4 (x cos (\frac{πn x}{4}) - \int - \frac{πn}{4} x sin (\frac{πn x}{4}) d x)

\int - \frac{πn}{4} x sin (\frac{πn x}{4}) d x = x cos (\frac{πn x}{4}) - \frac{4}{πn} sin (\frac{πn x}{4})

= 4 (x cos (\frac{πn x}{4}) - (x cos (\frac{πn x}{4}) - \frac{4}{πn} sin (\frac{πn x}{4})))

Simplify

4 (x cos (\frac{πn x}{4}) - (x cos (\frac{πn x}{4}) - \frac{4}{πn} sin (\frac{πn x}{4}))) : \frac{16}{πn} sin (\frac{πn x}{4})

= \frac{16}{πn} sin (\frac{πn x}{4})

Add a constant to the solution

= \frac{16}{πn} sin (\frac{πn x}{4}) + C

\frac{x}{x ^{2} + 0.0184}

x \to - 4 π lim (x + 15 cos (x + 4 π))

x \to - 4 lim (8 x + 1)

\int x^{4} e^{8 x^{5}} d x

f (x) = e^{3}

What is the integral of 4cos((npix)/4) ?
The integral of 4cos((npix)/4) is (16}{pin}sin(\frac{pinx)/4)+C