What is the tangent of f(x)=x^5,(1,1) ?

The tangent of f(x)=x^5,(1,1) is y=5x-4

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tangent of f(x)=x^5,(1,1)

tangent of

f (x) = x^{5}, (1, 1)

y = 5 x - 4

Solution steps

Find the slope of

f (x) = x^{5} : \frac{df ( x )}{d x} = 5 x^{4}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 5

Find the line with slope m=

5

and passing through

(1, 1) : y = 5 x - 4

y = 5 x - 4

\frac{d}{d x} (sec (x) tan (y))

\int 81 - x^{2} d x

\frac{d}{d x} (3 + x^{10} e^{x})

\int \frac{1}{2 ^{2} + 2 x ^{2}} d x

\frac{d y}{d x} = 4 x e^{(3 y)}