What is the integral of (sec^2(x)-4) ?

The integral of (sec^2(x)-4) is tan(x)-4x+C

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integral of (sec^2(x)-4)

\int (sec^{2} (x) - 4) d x

tan (x) - 4 x + C

Solution steps

\int sec^{2} (x) - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sec^{2} (x) d x - \int 4 d x

\int sec^{2} (x) d x = tan (x)

\int 4 d x = 4 x

= tan (x) - 4 x

Add a constant to the solution

= tan (x) - 4 x + C

x^{- 2}, 4

\int \frac{5}{4 x} d x

\int e^{- x - 1} d x

\frac{\partial}{\partial x} (sin (2 x + 5 y))

\int (tan^{4} (x)) d x

What is the integral of (sec^2(x)-4) ?
The integral of (sec^2(x)-4) is tan(x)-4x+C